w^2+10w-7200=0

Solution for w^2+10w-7200=0 equation:

w^2+10w-7200=0

a = 1; b = 10; c = -7200;
Δ = b2-4ac
Δ = 102-4·1·(-7200)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28900}=170$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-170}{2*1}=\frac{-180}{2}
=-90
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+170}{2*1}=\frac{160}{2}
=80
$